What is factor+25x^2-y^2+4y-4 ?

The solution to factor+25x^2-y^2+4y-4 is (5x+y-2)(5x-y+2)

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factor+25x^2-y^2+4y-4

factor

+ 25 x^{2} - y^{2} + 4 y - 4

(5 x + y - 2) (5 x - y + 2)

Solution steps

25 x^{2} - y^{2} + 4 y - 4

Factor

- y^{2} + 4 y - 4 : - (y - 2)^{2}

= 25 x^{2} - (y - 2)^{2}

Simplify

25 x^{2} : (5 x)^{2}

= (5 x)^{2} - (y - 2)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x)^{2} - (y - 2)^{2} = (5 x + (y - 2)) (5 x - (y - 2))

= (5 x + (y - 2)) (5 x - (y - 2))

Simplify

(5 x + (y - 2)) (5 x - (y - 2)) : (5 x + y - 2) (5 x - y + 2)

= (5 x + y - 2) (5 x - y + 2)

0.5!

17 + 7

45 - 9

9 - 8

\frac{56}{62}

What is factor+25x^2-y^2+4y-4 ?
The solution to factor+25x^2-y^2+4y-4 is (5x+y-2)(5x-y+2)