What is factor+4p^2-25q^2 ?

The solution to factor+4p^2-25q^2 is (2p+5q)(2p-5q)

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factor+4p^2-25q^2

factor

+ 4 p^{2} - 25 q^{2}

(2 p + 5 q) (2 p - 5 q)

Solution steps

4 p^{2} - 25 q^{2}

4 p^{2} = (2 p)^{2}

25 q^{2} = (5 q)^{2}

= (2 p)^{2} - (5 q)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 p)^{2} - (5 q)^{2} = (2 p + 5 q) (2 p - 5 q)

= (2 p + 5 q) (2 p - 5 q)

- \frac{5}{2} \cdot \frac{2}{5}

60 \div 30

+ 10 w^{10} - 19 w^{9} + 6 w^{8}

x \to \infty lim (- e^{x})

3 a^{2} - 9