What is expand (x+5)(2x^2-3x+3) ?

The solution to expand (x+5)(2x^2-3x+3) is 2x^3+7x^2-12x+15

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expand (x+5)(2x^2-3x+3)

expand

(x + 5) (2 x^{2} - 3 x + 3)

2 x^{3} + 7 x^{2} - 12 x + 15

Solution steps

(x + 5) (2 x^{2} - 3 x + 3)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 3 x) + x \cdot 3 + 5 \cdot 2 x^{2} + 5 (- 3 x) + 5 \cdot 3

Simplify

x \cdot 2 x^{2} + x (- 3 x) + x \cdot 3 + 5 \cdot 2 x^{2} + 5 (- 3 x) + 5 \cdot 3 : 2 x^{3} + 7 x^{2} - 12 x + 15

= 2 x^{3} + 7 x^{2} - 12 x + 15

\frac{1.2 \cdot 1 0 ^{7}}{2 \cdot 1 0 ^{3}}

7 \times 7 \times 7 \times 7 \times 7

3 x - (\frac{1}{3} x + 1)

3 x y + 2 y - 12 x - 8

9.8 n - (9 p + 9.9)

What is expand (x+5)(2x^2-3x+3) ?
The solution to expand (x+5)(2x^2-3x+3) is 2x^3+7x^2-12x+15