What are the solutions to the equation y^2+13=6y ?

The solutions to the equation y^2+13=6y are y=3+2i,y=3-2i

Find the zeros of y^2+13=6y

The zeros of y^2+13=6y are y=3+2i,y=3-2i

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y^{2} + 13 = 6 y

y = 3 + 2 i, y = 3 - 2 i

Solution steps

y^{2} + 13 = 6 y

Move

6 y

to the left side

y^{2} + 13 - 6 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 6 y + 13 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

y_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

y = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

y = 3 + 2 i, y = 3 - 2 i

4 = 0

5 x + 20 < - 3 (x - 5)

x^{2} - 5 x = - 4

(x^{2})^{1}

2 (\frac{1}{3} - x) + \frac{x}{2} > 3

What are the solutions to the equation y^2+13=6y ?
The solutions to the equation y^2+13=6y are y=3+2i,y=3-2i
Find the zeros of y^2+13=6y
The zeros of y^2+13=6y are y=3+2i,y=3-2i