What is 5i\times i\times (-2)i ?

The solution to 5i\times i\times (-2)i is 10i

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simplify 5i\times i\times (-2)i

simplify

5 i \cdot i \cdot (- 2) i

10 i

Solution steps

5 ii (- 2) i

Multiply the numbers:

5 (- 2) = - 10

= - 10 iii

Apply exponent rule:

aaa = a^{3}

iii = i^{3}

= - 10 i^{3}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

i^{3} = i^{2} i

= - 10 i^{2} i

Apply imaginary number rule:

i^{2} = - 1

= - 10 (- 1 i)

Apply rule:

1 \cdot a = a

- 1 i = - i

= - 10 (- i)

Apply rule:

- a (- b) = ab

- 10 (- i) = 10 i

= 10 i

lo g_{10} (0.00001)

\frac{a}{a + b} + \frac{b}{a - b}

\frac{1}{5} \div 6

0. 4^{- 2}

\frac{10}{8} + \frac{10}{6}