What is factor d^2-5d+4 ?

The solution to factor d^2-5d+4 is (d-1)(d-4)

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factor d^2-5d+4

factor

d^{2} - 5 d + 4

(d - 1) (d - 4)

Solution steps

d^{2} - 5 d + 4

Break the expression into groups

= (d^{2} - d) + (- 4 d + 4)

Factor out

d

from

d^{2} - d : d (d - 1)

Factor out

- 4

from

- 4 d + 4 : - 4 (d - 1)

= d (d - 1) - 4 (d - 1)

Factor out common term

d - 1

= (d - 1) (d - 4)

(- 1)^{n} + (- 1)^{n}

2 \frac{14}{25}

- i^{6}

(6 y - 5)^{2}

\frac{( - 8 ) ^{4}}{- 8}