What is factor a^7b^6-a^5b^4+a^4b^8-a^4b^4 ?

The solution to factor a^7b^6-a^5b^4+a^4b^8-a^4b^4 is a^4b^4(a^3b^2-a+b^4-1)

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factor a^7b^6-a^5b^4+a^4b^8-a^4b^4

factor

a^{7} b^{6} - a^{5} b^{4} + a^{4} b^{8} - a^{4} b^{4}

a^{4} b^{4} (a^{3} b^{2} - a + b^{4} - 1)

Solution steps

a^{7} b^{6} - a^{5} b^{4} + a^{4} b^{8} - a^{4} b^{4}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

a^{7} b^{6} = a^{4} a^{3} b^{4} b^{2}, a^{5} b^{4} = a^{4} a b^{4}, a^{4} b^{8} = a^{4} b^{4} b^{4}

= a^{4} a^{3} b^{4} b^{2} - a^{4} a b^{4} + a^{4} b^{4} b^{4} - a^{4} b^{4}

Factor out common term

a^{4} b^{4}

= a^{4} b^{4} (a^{3} b^{2} - a + b^{4} - 1)

(7 - i)^{2}

\frac{x - 1}{2} = \frac{x - 9}{11}

\frac{- 4}{- 8}

ln (1.3)

10 x - 79 = 2 x + 49

What is factor a^7b^6-a^5b^4+a^4b^8-a^4b^4 ?
The solution to factor a^7b^6-a^5b^4+a^4b^8-a^4b^4 is a^4b^4(a^3b^2-a+b^4-1)