simplify 8/(2+2i)

Solution

simplify

\frac{8}{2 + 2 i}

2 - 2 i

Solution steps

\frac{8}{2 + 2 i}

Multiply by the conjugate

\frac{2 - 2 i}{2 - 2 i}

= \frac{8 ( 2 - 2 i )}{( 2 + 2 i ) ( 2 - 2 i )}

Simplify

\frac{8 ( 2 - 2 i )}{( 2 + 2 i ) ( 2 - 2 i )} : \frac{16 - 16 i}{8}

= \frac{16 - 16 i}{8}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{16}{8} + \frac{- 16}{8} i

Simplify

\frac{16}{8} + \frac{- 16}{8} i : 2 - 2 i

= 2 - 2 i

\frac{x ^{6} + x ^{4} + x ^{2} + 1}{x ^{2} + 1}

146. 5^{2} - 109. 5^{2} + 27 \times 256

\frac{1}{2} \times x^{2}

lo g_{2} (4 n^{2})