What is (4xy+4xz)/(8xz+8x^2) ?

The solution to (4xy+4xz)/(8xz+8x^2) is (y+z)/(2(z+x))

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simplify (4xy+4xz)/(8xz+8x^2)

simplify

\frac{4 x y + 4 x z}{8 x z + 8 x ^{2}}

\frac{y + z}{2 ( z + x )}

Solution steps

\frac{4 x y + 4 x z}{8 x z + 8 x ^{2}}

Factor out common term

4 x : 4 x (y + z)

= \frac{4 x ( y + z )}{8 x z + 8 x ^{2}}

Factor

8 x z + 8 x^{2} : 8 x (z + x)

= \frac{4 x ( y + z )}{8 x ( z + x )}

Cancel the common factor:

x

= \frac{4 ( y + z )}{8 ( z + x )}

Factor the number:

8 = 4 \cdot 2

= \frac{4 ( y + z )}{4 \cdot 2 ( z + x )}

Cancel the common factor:

4

= \frac{y + z}{2 ( z + x )}

5 w^{2} - 20 = 0

9 = \frac{h}{9}

\frac{50}{2}

x^{2} = 4 x + 10

∣ 3 x + 2 ∣ = 5

What is (4xy+4xz)/(8xz+8x^2) ?
The solution to (4xy+4xz)/(8xz+8x^2) is (y+z)/(2(z+x))