What are the solutions to the equation 2x^2-2x=0 ?

The solutions to the equation 2x^2-2x=0 are x=1,x=0

Find the zeros of 2x^2-2x=0

The zeros of 2x^2-2x=0 are x=1,x=0

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2 x^{2} - 2 x = 0

x = 1, x = 0

Solution steps

2 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2}{2 \cdot 2} : 1

x = \frac{- ( - 2 ) - 2}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

5 x^{2} - 20 x + 3 = 0

10 x^{2} + 2 x y - 15 x - 3 y

\frac{m ^{\frac{2}{3}} n ^{2}}{m ^{- 1} n ^{3}}

7 (\frac{1}{2} x + 2) - 4 < - 5

36 a^{4} - 25 b^{4}

What are the solutions to the equation 2x^2-2x=0 ?
The solutions to the equation 2x^2-2x=0 are x=1,x=0
Find the zeros of 2x^2-2x=0
The zeros of 2x^2-2x=0 are x=1,x=0