What is (30a^{-3}b^{-6})/(-5a^{-6)b^{-3}} ?

The solution to (30a^{-3}b^{-6})/(-5a^{-6)b^{-3}} is -(6a^3)/(b^3)

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simplify (30a^{-3}b^{-6})/(-5a^{-6)b^{-3}}

simplify

\frac{30 a ^{- 3} b ^{- 6}}{- 5 a ^{- 6} b ^{- 3}}

- \frac{6 a ^{3}}{b ^{3}}

Solution steps

\frac{30 a ^{- 3} b ^{- 6}}{- 5 a ^{- 6} b ^{- 3}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{30 a ^{- 3} b ^{- 6}}{5 a ^{- 6} b ^{- 3}}

Divide the numbers:

\frac{30}{5} = 6

= \frac{6 a ^{- 3} b ^{- 6}}{a ^{- 6} b ^{- 3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{a ^{- 3}}{a ^{- 6}} = a^{- 3 - (- 6)}

= \frac{6 b ^{- 6} a ^{- 3 - (- 6)}}{b ^{- 3}}

Subtract the numbers:

- 3 - (- 6) = 3

= \frac{6 a ^{3} b ^{- 6}}{b ^{- 3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{b ^{- 6}}{b ^{- 3}} = \frac{1}{b ^{- 3 - (- 6)}}

= \frac{6 a ^{3}}{b ^{- 3 - (- 6)}}

Subtract the numbers:

- 3 - (- 6) = 3

= - \frac{6 a ^{3}}{b ^{3}}

3 y (2 x y)

\frac{2 - 4 i}{i}

+ 4 x^{2} - 12 x - 16

- x - 2 x^{2}

6 + \frac{4}{0}

What is (30a^{-3}b^{-6})/(-5a^{-6)b^{-3}} ?
The solution to (30a^{-3}b^{-6})/(-5a^{-6)b^{-3}} is -(6a^3)/(b^3)