What are the solutions to the equation 2^2+2^2=c^2 ?

The solutions to the equation 2^2+2^2=c^2 are c=2sqrt(2),c=-2sqrt(2)

Find the zeros of 2^2+2^2=c^2

The zeros of 2^2+2^2=c^2 are c=2sqrt(2),c=-2sqrt(2)

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2^{2} + 2^{2} = c^{2}

c = 22, c = - 22

Decimal Notation

c = 2.82842 \dots, c = - 2.82842 \dots

Solution steps

2^{2} + 2^{2} = c^{2}

Switch sides

c^{2} = 2^{2} + 2^{2}

Simplify

2^{2} + 2^{2} : 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 8, c = - 8

8 = 22

- 8 = - 22

c = 22, c = - 22

\frac{x ^{2}}{x ^{2} + x - 20}

lo g_{3} (- 2)

a^{4} - 2 a^{2} - 3

3 t + 1 < 10

3 \cdot 0.5

What are the solutions to the equation 2^2+2^2=c^2 ?
The solutions to the equation 2^2+2^2=c^2 are c=2sqrt(2),c=-2sqrt(2)
Find the zeros of 2^2+2^2=c^2
The zeros of 2^2+2^2=c^2 are c=2sqrt(2),c=-2sqrt(2)