What are the solutions to the equation k^2+8k=k ?

The solutions to the equation k^2+8k=k are k=0,k=-7

Find the zeros of k^2+8k=k

The zeros of k^2+8k=k are k=0,k=-7

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k^{2} + 8 k = k

k = 0, k = - 7

Solution steps

k^{2} + 8 k = k

Move

k

to the left side

k^{2} + 7 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

k_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 7 + 7}{2 \cdot 1}, k_{2} = \frac{- 7 - 7}{2 \cdot 1}

k = \frac{- 7 + 7}{2 \cdot 1} : 0

k = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = 0, k = - 7

- 4 \cdot (\frac{3}{- 4})

2 (\frac{4}{3})^{3}

3 (\frac{2}{3})

∣ 3 x + 12 ∣ \leq 5

3 c^{2} - 16 c + 5

What are the solutions to the equation k^2+8k=k ?
The solutions to the equation k^2+8k=k are k=0,k=-7
Find the zeros of k^2+8k=k
The zeros of k^2+8k=k are k=0,k=-7