What is (x^2-1)/(x^2-3x+2) ?

The solution to (x^2-1)/(x^2-3x+2) is (x+1)/(x-2)

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simplify (x^2-1)/(x^2-3x+2)

simplify

\frac{x ^{2} - 1}{x ^{2} - 3 x + 2}

\frac{x + 1}{x - 2}

Solution steps

\frac{x ^{2} - 1}{x ^{2} - 3 x + 2}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{x ^{2} - 3 x + 2}

Factor

x^{2} - 3 x + 2 : (x - 1) (x - 2)

= \frac{( x + 1 ) ( x - 1 )}{( x - 1 ) ( x - 2 )}

Cancel the common factor:

x - 1

= \frac{x + 1}{x - 2}

lo g_{7} (7)

6 (7 x + 3)

54 \times 3

54 \times 2

\frac{1}{1 1 ^{3}}