What are the solutions to the equation 3x^2-7=x^2+9 ?

The solutions to the equation 3x^2-7=x^2+9 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 3x^2-7=x^2+9

The zeros of 3x^2-7=x^2+9 are x=2sqrt(2),x=-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 7 = x^{2} + 9

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

3 x^{2} - 7 = x^{2} + 9

Move

7

to the right side

3 x^{2} = x^{2} + 16

Move

x^{2}

to the left side

2 x^{2} = 16

Divide both sides by

2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

64 c^{3} - 56 c^{2} + 88 c

- 10250 - 10500 - 1540

3 < - 5 n + 2 n

3 x^{2} - 1 \geq 6

6 x^{2} - 37 x + 6

What are the solutions to the equation 3x^2-7=x^2+9 ?
The solutions to the equation 3x^2-7=x^2+9 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 3x^2-7=x^2+9
The zeros of 3x^2-7=x^2+9 are x=2sqrt(2),x=-2sqrt(2)