What is (9k^{-9})/(3k*k) ?

The solution to (9k^{-9})/(3k*k) is 3/(k^{11)}

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simplify (9k^{-9})/(3k*k)

simplify

\frac{9 k ^{- 9}}{3 k \cdot k}

\frac{3}{k ^{11}}

Solution steps

\frac{9 k ^{- 9}}{3 kk}

Apply exponent rule:

aa = a^{2}

kk = k^{2}

= \frac{9 k ^{- 9}}{3 k ^{2}}

Factor the number:

9 = 3 \cdot 3

= \frac{3 \cdot 3 k ^{- 9}}{3 k ^{2}}

Cancel the common factor:

3

= \frac{3 k ^{- 9}}{k ^{2}}

Simplify

\frac{k ^{- 9}}{k ^{2}} : \frac{1}{k ^{11}}

= \frac{3}{k ^{11}}

- 3 \times (- \frac{1}{3})

- 3 \times (- \frac{1}{2})

\frac{8}{5} \div 2

(x + y)^{2} + 2 (x + y) + 1

3^{2} - 1^{2}