What is expand (x+3)(2x^2-4x-1) ?

The solution to expand (x+3)(2x^2-4x-1) is 2x^3+2x^2-13x-3

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expand (x+3)(2x^2-4x-1)

expand

(x + 3) (2 x^{2} - 4 x - 1)

2 x^{3} + 2 x^{2} - 13 x - 3

Solution steps

(x + 3) (2 x^{2} - 4 x - 1)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 4 x) + x (- 1) + 3 \cdot 2 x^{2} + 3 (- 4 x) + 3 (- 1)

Simplify

x \cdot 2 x^{2} + x (- 4 x) + x (- 1) + 3 \cdot 2 x^{2} + 3 (- 4 x) + 3 (- 1) : 2 x^{3} + 2 x^{2} - 13 x - 3

= 2 x^{3} + 2 x^{2} - 13 x - 3

3.75

\frac{4}{3} \div 3

(i w)^{2}

- 10 0^{\frac{3}{2}}

5 \times 17

What is expand (x+3)(2x^2-4x-1) ?
The solution to expand (x+3)(2x^2-4x-1) is 2x^3+2x^2-13x-3