What are the solutions to the equation u^2-38u=0 ?

The solutions to the equation u^2-38u=0 are u=38,u=0

Find the zeros of u^2-38u=0

The zeros of u^2-38u=0 are u=38,u=0

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u^{2} - 38 u = 0

u = 38, u = 0

Solution steps

u^{2} - 38 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 38)^{2} - 4 \cdot 1 \cdot 0 = 38

u_{1, 2} = \frac{- ( - 38 ) \pm 38}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 38 ) + 38}{2 \cdot 1}, u_{2} = \frac{- ( - 38 ) - 38}{2 \cdot 1}

u = \frac{- ( - 38 ) + 38}{2 \cdot 1} : 38

u = \frac{- ( - 38 ) - 38}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

u = 38, u = 0

58 + 220 - 8

4 (x - 6) = 7 x + 8

1000

x^{2} - 14 x = - 45

102 4^{\frac{3}{5}}

What are the solutions to the equation u^2-38u=0 ?
The solutions to the equation u^2-38u=0 are u=38,u=0
Find the zeros of u^2-38u=0
The zeros of u^2-38u=0 are u=38,u=0