What is (x^3-13x^2+47x-35)/(x-1) ?

The solution to (x^3-13x^2+47x-35)/(x-1) is (x-5)(x-7)

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simplify (x^3-13x^2+47x-35)/(x-1)

simplify

\frac{x ^{3} - 13 x ^{2} + 47 x - 35}{x - 1}

(x - 5) (x - 7)

Solution steps

\frac{x ^{3} - 13 x ^{2} + 47 x - 35}{x - 1}

Use the rational root theorem

= \frac{( x - 1 ) \frac{x ^{3} - 13 x ^{2} + 47 x - 35}{x - 1}}{x - 1}

\frac{x ^{3} - 13 x ^{2} + 47 x - 35}{x - 1} = x^{2} - 12 x + 35

= \frac{( x - 1 ) ( x ^{2} - 12 x + 35 )}{x - 1}

Factor

x^{2} - 12 x + 35 : (x - 5) (x - 7)

= \frac{( x - 1 ) ( x - 5 ) ( x - 7 )}{x - 1}

Cancel the common factor:

x - 1

= (x - 5) (x - 7)

\frac{5}{4 3}

36 \cdot 1 0^{- 3}

(5.8) (- 6.2)

2^{3} \times 2^{5}

1 2^{2} + (- 5)^{2}

What is (x^3-13x^2+47x-35)/(x-1) ?
The solution to (x^3-13x^2+47x-35)/(x-1) is (x-5)(x-7)