What is (-1-2i)/(i-2) ?

The solution to (-1-2i)/(i-2) is i

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simplify (-1-2i)/(i-2)

simplify

\frac{- 1 - 2 i}{i - 2}

i

Solution steps

\frac{- 1 - 2 i}{i - 2}

Rewrite

i - 2

in standard complex form:

- 2 + i

= \frac{- 1 - 2 i}{- 2 + i}

Multiply by the conjugate

\frac{- 2 - i}{- 2 - i}

= \frac{( - 1 - 2 i ) ( - 2 - i )}{( - 2 + i ) ( - 2 - i )}

Simplify

\frac{( - 1 - 2 i ) ( - 2 - i )}{( - 2 + i ) ( - 2 - i )} : \frac{5 i}{5}

= \frac{5 i}{5}

Cancel the common factor:

5

= i

8 p + 12

2^{5} \times 2^{3}

x^{6} - 6 x^{3} - 16

+ \frac{6 i}{9 - 9 i}

3 \times 3 x^{2}