What is factor b^2-19b+90 ?

The solution to factor b^2-19b+90 is (b-9)(b-10)

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factor b^2-19b+90

factor

b^{2} - 19 b + 90

(b - 9) (b - 10)

Solution steps

b^{2} - 19 b + 90

Break the expression into groups

= (b^{2} - 9 b) + (- 10 b + 90)

Factor out

b

from

b^{2} - 9 b : b (b - 9)

Factor out

- 10

from

- 10 b + 90 : - 10 (b - 9)

= b (b - 9) - 10 (b - 9)

Factor out common term

b - 9

= (b - 9) (b - 10)

\frac{3}{2} \times \frac{1}{2}

75 \times 2

3^{2} \times 3^{4}

\frac{10 x ^{2} y ^{3}}{4 x ^{5} y ^{2}}