What is factor 2k^3+9k^2+13k+6 ?

The solution to factor 2k^3+9k^2+13k+6 is (k+1)(2k+3)(k+2)

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factor 2k^3+9k^2+13k+6

factor

2 k^{3} + 9 k^{2} + 13 k + 6

(k + 1) (2 k + 3) (k + 2)

Solution steps

2 k^{3} + 9 k^{2} + 13 k + 6

Use the rational root theorem

= (k + 1) \frac{2 k ^{3} + 9 k ^{2} + 13 k + 6}{k + 1}

\frac{2 k ^{3} + 9 k ^{2} + 13 k + 6}{k + 1} = 2 k^{2} + 7 k + 6

= (k + 1) (2 k^{2} + 7 k + 6)

Factor

2 k^{2} + 7 k + 6 : (2 k + 3) (k + 2)

= (k + 1) (2 k + 3) (k + 2)

∣ x - 7 ∣ - 3 \geq 8

\frac{9}{8}

(3^{- 4})^{7}

- 4 (2 x - 1) > 5 - 3 x

(n^{2})^{3}

What is factor 2k^3+9k^2+13k+6 ?
The solution to factor 2k^3+9k^2+13k+6 is (k+1)(2k+3)(k+2)