What is factor+4z^2-20z+25 ?

The solution to factor+4z^2-20z+25 is (2z-5)^2

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factor+4z^2-20z+25

factor

+ 4 z^{2} - 20 z + 25

(2 z - 5)^{2}

Solution steps

4 z^{2} - 20 z + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 z^{2} = (2 z)^{2}

25 = 5^{2}

- 20 z = - 2 \cdot 2 z \cdot 5

= (2 z)^{2} - 2 \cdot 2 z \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 z)^{2} - 2 \cdot 2 z \cdot 5 + 5^{2} = (2 z - 5)^{2}

= (2 z - 5)^{2}

1000 e^{0.05 \cdot 7}

\frac{5 x ^{7} y ^{7}}{25 x ^{7} y ^{2}}

- 2 x \times (- 2) x

- 4 x^{2} - 16 x + 9

\frac{6.71732}{4.5 \cdot 1 0 ^{- 10}}