What is the answer to (x-4)^2=x(x-9)+40 ?

The answer to (x-4)^2=x(x-9)+40 is x=24

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(x-4)^2=x(x-9)+40

(x - 4)^{2} = x (x - 9) + 40

x = 24

Solution steps

(x - 4)^{2} = x (x - 9) + 40

Expand

x (x - 9) : x^{2} - 9 x

x^{2} - 8 x + 16 = x^{2} - 9 x + 40

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

x^{2} - 8 x + 16 = x^{2} - 9 x + 40

Move

16

to the right side

x^{2} - 8 x = x^{2} - 9 x + 24

Subtract

x^{2} - 9 x

from both sides

x^{2} - 8 x - (x^{2} - 9 x) = x^{2} - 9 x + 24 - (x^{2} - 9 x)

Simplify

x = 24

z^{4} - 16

(p^{6})^{2}

\frac{2.3 \cdot 1 0 ^{- 4}}{1.3 \cdot 1 0 ^{- 3}}

4 x^{\frac{5}{4}} - 2 x^{\frac{1}{4}}

What is the answer to (x-4)^2=x(x-9)+40 ?
The answer to (x-4)^2=x(x-9)+40 is x=24
Solve for x: (x-4)^2=x(x-9)+40
The solution is x=24