What are the solutions to the equation 5x^2+6x=-9 ?

The solutions to the equation 5x^2+6x=-9 are x=-3/5+i 6/5 ,x=-3/5-i 6/5

Find the zeros of 5x^2+6x=-9

The zeros of 5x^2+6x=-9 are x=-3/5+i 6/5 ,x=-3/5-i 6/5

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5 x^{2} + 6 x = - 9

x = - \frac{3}{5} + i \frac{6}{5}, x = - \frac{3}{5} - i \frac{6}{5}

Solution steps

5 x^{2} + 6 x = - 9

Move

9

to the left side

5 x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 \cdot 9}{2 \cdot 5}

Simplify

6^{2} - 4 \cdot 5 \cdot 9 : 12 i

x_{1, 2} = \frac{- 6 \pm 12 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 12 i}{2 \cdot 5}, x_{2} = \frac{- 6 - 12 i}{2 \cdot 5}

x = \frac{- 6 + 12 i}{2 \cdot 5} : - \frac{3}{5} + i \frac{6}{5}

x = \frac{- 6 - 12 i}{2 \cdot 5} : - \frac{3}{5} - i \frac{6}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{6}{5}, x = - \frac{3}{5} - i \frac{6}{5}

7 (2 - 3 n) = 49

2 x^{2} = 20

(5 m^{2} - 3 m^{2} + 6) \cdot (- 3 m + 2)

x^{3} - x > 0

x + 8 = 14

What are the solutions to the equation 5x^2+6x=-9 ?
The solutions to the equation 5x^2+6x=-9 are x=-3/5+i 6/5 ,x=-3/5-i 6/5
Find the zeros of 5x^2+6x=-9
The zeros of 5x^2+6x=-9 are x=-3/5+i 6/5 ,x=-3/5-i 6/5