What is expand (3x+2)(3x^2-3x-7) ?

The solution to expand (3x+2)(3x^2-3x-7) is 9x^3-3x^2-27x-14

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expand (3x+2)(3x^2-3x-7)

expand

(3 x + 2) (3 x^{2} - 3 x - 7)

9 x^{3} - 3 x^{2} - 27 x - 14

Solution steps

(3 x + 2) (3 x^{2} - 3 x - 7)

Distribute parentheses

= 3 x \cdot 3 x^{2} + 3 x (- 3 x) + 3 x (- 7) + 2 \cdot 3 x^{2} + 2 (- 3 x) + 2 (- 7)

Simplify

3 x \cdot 3 x^{2} + 3 x (- 3 x) + 3 x (- 7) + 2 \cdot 3 x^{2} + 2 (- 3 x) + 2 (- 7) : 9 x^{3} - 3 x^{2} - 27 x - 14

= 9 x^{3} - 3 x^{2} - 27 x - 14

\frac{2 π}{\frac{2}{8}}

7 + 43 - 7 - 43

0.36

(- 2 e^{- 2 x})^{2}

\frac{( y ^{3} ) ( y ^{8} )}{( y ^{1} ) ( y - 3 )}

What is expand (3x+2)(3x^2-3x-7) ?
The solution to expand (3x+2)(3x^2-3x-7) is 9x^3-3x^2-27x-14