What is (2-6i)-(-10+4i) ?

The solution to (2-6i)-(-10+4i) is 12-10i

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simplify (2-6i)-(-10+4i)

simplify

(2 - 6 i) - (- 10 + 4 i)

12 - 10 i

Solution steps

(2 - 6 i) - (- 10 + 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (2 - (- 10)) + (- 6 - 4) i

Simplify

(2 - (- 10)) + (- 6 - 4) i : 12 - 10 i

= 12 - 10 i

- 9 x^{2} + 6 x - 1

y - 3 y + 2 y

10 \times 20

(2 x + 2) (6 x + 1)

\frac{9}{7 x} + \frac{2}{9 x}