What are the solutions to the equation x^2+19x=-90 ?

The solutions to the equation x^2+19x=-90 are x=-9,x=-10

Find the zeros of x^2+19x=-90

The zeros of x^2+19x=-90 are x=-9,x=-10

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x^{2} + 19 x = - 90

x = - 9, x = - 10

Solution steps

x^{2} + 19 x = - 90

Move

90

to the left side

x^{2} + 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 1}, x_{2} = \frac{- 19 - 1}{2 \cdot 1}

x = \frac{- 19 + 1}{2 \cdot 1} : - 9

x = \frac{- 19 - 1}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 9, x = - 10

9 x^{2} - 17 x - 2 = 0

(x + 2)^{2} - 9 = 0

\frac{1}{3} \cdot \frac{5}{6}

\frac{- 6 + - 54}{3}

x^{2} - 2 x - 8 x

What are the solutions to the equation x^2+19x=-90 ?
The solutions to the equation x^2+19x=-90 are x=-9,x=-10
Find the zeros of x^2+19x=-90
The zeros of x^2+19x=-90 are x=-9,x=-10