What is (15m^4n^3-35mn^2)/(5mn) ?

The solution to (15m^4n^3-35mn^2)/(5mn) is n(3m^3n-7)

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simplify (15m^4n^3-35mn^2)/(5mn)

simplify

\frac{15 m ^{4} n ^{3} - 35 m n ^{2}}{5 mn}

n (3 m^{3} n - 7)

Solution steps

\frac{15 m ^{4} n ^{3} - 35 m n ^{2}}{5 mn}

Factor

15 m^{4} n^{3} - 35 m n^{2} : 5 m n^{2} (3 m^{3} n - 7)

= \frac{5 m n ^{2} ( 3 m ^{3} n - 7 )}{5 mn}

Cancel the common factor:

5

= \frac{m n ^{2} ( 3 m ^{3} n - 7 )}{mn}

Cancel the common factor:

m

= \frac{n ^{2} ( 3 m ^{3} n - 7 )}{n}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

n^{2} = nn

= \frac{nn ( 3 m ^{3} n - 7 )}{n}

Cancel the common factor:

n

= n (3 m^{3} n - 7)

\frac{x ^{2} + 2 x y + y ^{2}}{x ^{2} - y ^{2}}

6 \times 1 0^{- 2}

\frac{\frac{77}{9}}{2.5}

38

2 x - 9 x

What is (15m^4n^3-35mn^2)/(5mn) ?
The solution to (15m^4n^3-35mn^2)/(5mn) is n(3m^3n-7)