What is (3/2 x^{-7})(2x^{-1})^5 ?

The solution to (3/2 x^{-7})(2x^{-1})^5 is (48)/(x^{12)}

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simplify (3/2 x^{-7})(2x^{-1})^5

simplify

(\frac{3}{2} x^{- 7}) (2 x^{- 1})^{5}

\frac{48}{x ^{12}}

Solution steps

(\frac{3}{2} x^{- 7}) (2 x^{- 1})^{5}

Simplify

\frac{3}{2} x^{- 7} : \frac{3}{2 x ^{7}}

= \frac{3}{2 x ^{7}} (2 x^{- 1})^{5}

Simplify

(2 x^{- 1})^{5} : \frac{32}{x ^{5}}

= \frac{3}{2 x ^{7}} \cdot \frac{32}{x ^{5}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 32}{2 x ^{7} x ^{5}}

Cancel

\frac{3 \cdot 32}{2 x ^{7} x ^{5}} : \frac{3 \cdot 16}{x ^{7} x ^{5}}

= \frac{3 \cdot 16}{x ^{7} x ^{5}}

Multiply the numbers:

3 \cdot 16 = 48

= \frac{48}{x ^{7} x ^{5}}

Simplify

x^{7} x^{5} : x^{12}

= \frac{48}{x ^{12}}

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What is (3/2 x^{-7})(2x^{-1})^5 ?
The solution to (3/2 x^{-7})(2x^{-1})^5 is (48)/(x^{12)}