What is the d/(dp)(e^{(ipi)/2}) ?

The d/(dp)(e^{(ipi)/2}) is e^{(ipi)/2}(-1/2)

What is the first d/(dp)(e^{(ipi)/2}) ?

The first d/(dp)(e^{(ipi)/2}) is e^{(ipi)/2}(-1/2)

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\frac{d}{d p} (e^{\frac{i p i}{2}})

e^{\frac{i p i}{2}} (- \frac{1}{2})

Solution steps

\frac{d}{d p} (e^{\frac{i p i}{2}})

Apply the chain rule:

e^{\frac{i p i}{2}} \frac{d}{d p} (\frac{i p i}{2})

= e^{\frac{i p i}{2}} \frac{d}{d p} (\frac{i p i}{2})

\frac{d}{d p} (\frac{i p i}{2}) = - \frac{1}{2}

= e^{\frac{i p i}{2}} (- \frac{1}{2})

\frac{1}{6} \times 0.3

3 x \times (- 2)

(2 x + 1) (2 x + 2)

20 lo g_{10} (1)

(4 x^{3} y^{5})^{2}

What is the d/(dp)(e^{(ipi)/2}) ?
The d/(dp)(e^{(ipi)/2}) is e^{(ipi)/2}(-1/2)
What is the first d/(dp)(e^{(ipi)/2}) ?
The first d/(dp)(e^{(ipi)/2}) is e^{(ipi)/2}(-1/2)