What are the solutions to the equation 4^2+7^2=c^2 ?

The solutions to the equation 4^2+7^2=c^2 are c=sqrt(65),c=-sqrt(65)

Find the zeros of 4^2+7^2=c^2

The zeros of 4^2+7^2=c^2 are c=sqrt(65),c=-sqrt(65)

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4^{2} + 7^{2} = c^{2}

c = 65, c = - 65

Solution steps

4^{2} + 7^{2} = c^{2}

Switch sides

c^{2} = 4^{2} + 7^{2}

Simplify

4^{2} + 7^{2} : 65

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 65, c = - 65

44 x^{2} z^{5} + 11 x^{3} y^{3} z^{2}

- 18 - 6 x = 6 (1 + 3 x)

\frac{1}{2 a} - \frac{2}{3 b} + 14 + \frac{1}{7 a}

(8 + 9 i)^{2}

(x + 2) (x - 3) (x + 8) \geq 0

What are the solutions to the equation 4^2+7^2=c^2 ?
The solutions to the equation 4^2+7^2=c^2 are c=sqrt(65),c=-sqrt(65)
Find the zeros of 4^2+7^2=c^2
The zeros of 4^2+7^2=c^2 are c=sqrt(65),c=-sqrt(65)