What is expand (2x+1)(3x^2+3x-2) ?

The solution to expand (2x+1)(3x^2+3x-2) is 6x^3+9x^2-x-2

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expand (2x+1)(3x^2+3x-2)

expand

(2 x + 1) (3 x^{2} + 3 x - 2)

6 x^{3} + 9 x^{2} - x - 2

Solution steps

(2 x + 1) (3 x^{2} + 3 x - 2)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x \cdot 3 x + 2 x (- 2) + 1 \cdot 3 x^{2} + 1 \cdot 3 x + 1 \cdot (- 2)

Simplify

2 x \cdot 3 x^{2} + 2 x \cdot 3 x + 2 x (- 2) + 1 \cdot 3 x^{2} + 1 \cdot 3 x + 1 \cdot (- 2) : 6 x^{3} + 9 x^{2} - x - 2

= 6 x^{3} + 9 x^{2} - x - 2

lo g_{0.1} (0.01)

- 5 - \frac{3}{2}

\frac{4}{3} \div \frac{11}{8}

2.84 \cdot 1 0^{7} \cdot 4.15 \cdot 1 0^{- 5}

8, 20

What is expand (2x+1)(3x^2+3x-2) ?
The solution to expand (2x+1)(3x^2+3x-2) is 6x^3+9x^2-x-2