What are the solutions to the equation x^2=25x ?

The solutions to the equation x^2=25x are x=25,x=0

Find the zeros of x^2=25x

The zeros of x^2=25x are x=25,x=0

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x^{2} = 25 x

x = 25, x = 0

Solution steps

x^{2} = 25 x

Move

25 x

to the left side

x^{2} - 25 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 0 = 25

x_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 1}

x = \frac{- ( - 25 ) + 25}{2 \cdot 1} : 25

x = \frac{- ( - 25 ) - 25}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 25, x = 0

lo g_{\frac{1}{2}} (\frac{1}{16})

5^{\frac{5}{4}}

(\frac{81}{16})^{\frac{3}{4}}

- 7 x^{3} + 14 x^{2} y - 7 x y^{2}

3 y^{2} + y - 5 = 0

What are the solutions to the equation x^2=25x ?
The solutions to the equation x^2=25x are x=25,x=0
Find the zeros of x^2=25x
The zeros of x^2=25x are x=25,x=0