What is the domain of f(n)=(6n^2+8n+2)/(2n^2-2) ?

The domain of f(n)=(6n^2+8n+2)/(2n^2-2) is n 1

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domain of f(n)=(6n^2+8n+2)/(2n^2-2)

domain

f (n) = \frac{6 n ^{2} + 8 n + 2}{2 n ^{2} - 2}

n < - 1 or - 1 < n < 1 or n > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

n = 1, n = - 1

The function domain

n < - 1 or - 1 < n < 1 or n > 1

- \frac{5}{6} + \frac{3}{4} + \frac{5}{18}

\frac{7.3 - 6.3}{0.2} - 11.6

- 10 - 11

8 \times 32

8 \times (- 5)

What is the domain of f(n)=(6n^2+8n+2)/(2n^2-2) ?
The domain of f(n)=(6n^2+8n+2)/(2n^2-2) is n<-1\lor-1<n<1\lor n>1