What is expand (3x+8)(2x^2-3x+3) ?

The solution to expand (3x+8)(2x^2-3x+3) is 6x^3+7x^2-15x+24

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expand (3x+8)(2x^2-3x+3)

expand

(3 x + 8) (2 x^{2} - 3 x + 3)

6 x^{3} + 7 x^{2} - 15 x + 24

Solution steps

(3 x + 8) (2 x^{2} - 3 x + 3)

Distribute parentheses

= 3 x \cdot 2 x^{2} + 3 x (- 3 x) + 3 x \cdot 3 + 8 \cdot 2 x^{2} + 8 (- 3 x) + 8 \cdot 3

Simplify

3 x \cdot 2 x^{2} + 3 x (- 3 x) + 3 x \cdot 3 + 8 \cdot 2 x^{2} + 8 (- 3 x) + 8 \cdot 3 : 6 x^{3} + 7 x^{2} - 15 x + 24

= 6 x^{3} + 7 x^{2} - 15 x + 24

52 \times 2

- 3 x - 15

24 x^{2} - 30 x + 9

15 x^{2} - 18 x - 24

- \frac{1}{2} \times 8

What is expand (3x+8)(2x^2-3x+3) ?
The solution to expand (3x+8)(2x^2-3x+3) is 6x^3+7x^2-15x+24