What is r+5(-2r-10)<=-4r-1+6r ?

The solution to r+5(-2r-10) =-49/11

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r+5(-2r-10)<=-4r-1+6r

r + 5 (- 2 r - 10) \leq - 4 r - 1 + 6 r

r \geq - \frac{49}{11}

Interval Notation

[- \frac{49}{11}, \infty)

Decimal Notation

r \geq - 4.45454 \dots

Solution steps

r + 5 (- 2 r - 10) \leq - 4 r - 1 + 6 r

Group like terms

r + 5 (- 2 r - 10) \leq - 4 r + 6 r - 1

Add similar elements:

- 4 r + 6 r = 2 r

r + 5 (- 2 r - 10) \leq 2 r - 1

Expand

5 (- 2 r - 10) : - 10 r - 50

r - 10 r - 50 \leq 2 r - 1

Add similar elements:

r - 10 r = - 9 r

- 9 r - 50 \leq 2 r - 1

Move

50

to the right side

- 9 r \leq 2 r + 49

Move

2 r

to the left side

- 11 r \leq 49

Multiply both sides by

- 1

11 r \geq - 49

Divide both sides by

11

r \geq - \frac{49}{11}

m^{2} - 16

x^{4} - 16 x^{2}

81 x^{4} - 256

\frac{5 ^{1} e ^{- 5}}{1 !}

- 12 + 6 = s

What is r+5(-2r-10)<=-4r-1+6r ?
The solution to r+5(-2r-10)<=-4r-1+6r is r>=-49/11