What are the solutions to the equation x^2+10x+8=x ?

The solutions to the equation x^2+10x+8=x are x=-1,x=-8

Find the zeros of x^2+10x+8=x

The zeros of x^2+10x+8=x are x=-1,x=-8

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x^{2} + 10 x + 8 = x

x = - 1, x = - 8

Solution steps

x^{2} + 10 x + 8 = x

Move

x

to the left side

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

(x - 9)^{\frac{7}{2}} - 81 (x - 9)^{\frac{3}{2}}

15 + 2 x \geq - x + 33

(- 2)^{- 3}

729 - 16 t^{2}

\frac{1}{7} - \frac{1}{9}

What are the solutions to the equation x^2+10x+8=x ?
The solutions to the equation x^2+10x+8=x are x=-1,x=-8
Find the zeros of x^2+10x+8=x
The zeros of x^2+10x+8=x are x=-1,x=-8