What is |2x^2-3|>= 5x ?

The solution to |2x^2-3|>= 5x is x = 3

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|2x^2-3|>= 5x

2 x^{2} - 3 \geq 5 x

x \leq \frac{1}{2} or x \geq 3

Solution steps

2 x^{2} - 3 \geq 5 x

Find positive and negative intervals

x \leq - \frac{3}{2}, - \frac{3}{2} < x < \frac{3}{2}, x \geq \frac{3}{2}

Solve the inequality for each interval

x \leq - \frac{3}{2} or - \frac{3}{2} < x \leq \frac{1}{2} or x \geq 3

Merge Overlapping Intervals

x \leq \frac{1}{2} or x \geq 3

310 \cdot 28

7 - 2 k \leq 3

p^{2} + 13 p + 22 = 0

7 x^{2} - 65 x + 18

\frac{3 ^{2}}{3 ^{- 4}}