What are the solutions to the equation 2z^2-21z-36=0 ?

The solutions to the equation 2z^2-21z-36=0 are z=12,z=-3/2

Find the zeros of 2z^2-21z-36=0

The zeros of 2z^2-21z-36=0 are z=12,z=-3/2

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2 z^{2} - 21 z - 36 = 0

z = 12, z = - \frac{3}{2}

Decimal Notation

z = 12, z = - 1.5

Solution steps

2 z^{2} - 21 z - 36 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 2 ( - 36 )}{2 \cdot 2}

(- 21)^{2} - 4 \cdot 2 (- 36) = 27

z_{1, 2} = \frac{- ( - 21 ) \pm 27}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- ( - 21 ) + 27}{2 \cdot 2}, z_{2} = \frac{- ( - 21 ) - 27}{2 \cdot 2}

z = \frac{- ( - 21 ) + 27}{2 \cdot 2} : 12

z = \frac{- ( - 21 ) - 27}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

z = 12, z = - \frac{3}{2}

\frac{560}{5}

\frac{n !}{( n - 3 ) ! + ( n - 2 ) !}

4 x (2 x + 1) + 1 (2 x + 1)

\frac{36}{169}

\frac{4 - 3 x}{11} = 2

What are the solutions to the equation 2z^2-21z-36=0 ?
The solutions to the equation 2z^2-21z-36=0 are z=12,z=-3/2
Find the zeros of 2z^2-21z-36=0
The zeros of 2z^2-21z-36=0 are z=12,z=-3/2