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Popular >

simplify 2^{log_{2}(n)-1}

Solution

simplify

2^{l o g_{2} (n) - 1}

Solution

\frac{1}{2} n

Solution steps

2^{l o g_{2} (n) - 1}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{l o g_{2} (n) - 1} = 2^{l o g_{2} (n)} \cdot 2^{- 1}

= 2^{l o g_{2} (n)} \cdot 2^{- 1}

2^{l o g_{2} (n)} = n

2^{- 1} = \frac{1}{2}

= n \frac{1}{2}

= \frac{1}{2} n

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Frequently Asked Questions (FAQ)

What is 2^{log_{2}(n)-1} ?
The solution to 2^{log_{2}(n)-1} is 1/2 n