What is (3x+7y)/(2z+9)+(3x-4y)/(2z+9) ?

The solution to (3x+7y)/(2z+9)+(3x-4y)/(2z+9) is (6x+3y)/(2z+9)

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simplify (3x+7y)/(2z+9)+(3x-4y)/(2z+9)

simplify

\frac{3 x + 7 y}{2 z + 9} + \frac{3 x - 4 y}{2 z + 9}

\frac{6 x + 3 y}{2 z + 9}

Solution steps

\frac{3 x + 7 y}{2 z + 9} + \frac{3 x - 4 y}{2 z + 9}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{3 x + 7 y + 3 x - 4 y}{2 z + 9}

Simplify

3 x + 7 y + 3 x - 4 y : 6 x + 3 y

= \frac{6 x + 3 y}{2 z + 9}

28 + 8

\frac{x}{2} \times x

(3 x^{4} - x^{2})^{3}

6 - 18

(1 + 10 i)^{2}

What is (3x+7y)/(2z+9)+(3x-4y)/(2z+9) ?
The solution to (3x+7y)/(2z+9)+(3x-4y)/(2z+9) is (6x+3y)/(2z+9)