What is factor x^4+6x^3+13x^2+12x+4 ?

The solution to factor x^4+6x^3+13x^2+12x+4 is (x+1)^2(x+2)^2

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factor x^4+6x^3+13x^2+12x+4

factor

x^{4} + 6 x^{3} + 13 x^{2} + 12 x + 4

(x + 1)^{2} (x + 2)^{2}

Solution steps

x^{4} + 6 x^{3} + 13 x^{2} + 12 x + 4

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 6 x ^{3} + 13 x ^{2} + 12 x + 4}{x + 1}

\frac{x ^{4} + 6 x ^{3} + 13 x ^{2} + 12 x + 4}{x + 1} = x^{3} + 5 x^{2} + 8 x + 4

= (x + 1) (x^{3} + 5 x^{2} + 8 x + 4)

Factor

x^{3} + 5 x^{2} + 8 x + 4 : (x + 1) (x + 2) (x + 2)

= (x + 1) (x + 1) (x + 2) (x + 2)

Simplify

= (x + 1)^{2} (x + 2)^{2}

9 56 x^{7} y^{12}

(1 - x) (1 - y)

7 - 3 + 6 + x

43 \times 26

What is factor x^4+6x^3+13x^2+12x+4 ?
The solution to factor x^4+6x^3+13x^2+12x+4 is (x+1)^2(x+2)^2