What is factor 2w^2+w-28 ?

The solution to factor 2w^2+w-28 is (2w-7)(w+4)

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factor 2w^2+w-28

factor

2 w^{2} + w - 28

(2 w - 7) (w + 4)

Solution steps

2 w^{2} + w - 28

Break the expression into groups

= (2 w^{2} - 7 w) + (8 w - 28)

Factor out

w

from

2 w^{2} - 7 w : w (2 w - 7)

Factor out

4

from

8 w - 28 : 4 (2 w - 7)

= w (2 w - 7) + 4 (2 w - 7)

Factor out common term

2 w - 7

= (2 w - 7) (w + 4)

6 r^{2} - r - 1 = 0

9^{2}

2 x^{2} + 4 = 7 x

\frac{m}{- 3} < 5

- 5 x = - 1