What is (28u^{-2}v^3)/(4u^2v^2) ?

The solution to (28u^{-2}v^3)/(4u^2v^2) is (7v)/(u^4)

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simplify (28u^{-2}v^3)/(4u^2v^2)

simplify

\frac{28 u ^{- 2} v ^{3}}{4 u ^{2} v ^{2}}

\frac{7 v}{u ^{4}}

Solution steps

\frac{28 u ^{- 2} v ^{3}}{4 u ^{2} v ^{2}}

Factor the number:

28 = 4 \cdot 7

= \frac{4 \cdot 7 u ^{- 2} v ^{3}}{4 u ^{2} v ^{2}}

Cancel the common factor:

4

= \frac{7 u ^{- 2} v ^{3}}{u ^{2} v ^{2}}

Simplify

\frac{v ^{3}}{v ^{2}} : v

= \frac{7 u ^{- 2} v}{u ^{2}}

Simplify

\frac{u ^{- 2}}{u ^{2}} : \frac{1}{u ^{4}}

= \frac{7 v}{u ^{4}}

42 - 22

\frac{12 - 3 i}{3}

\frac{14 x ^{3} y ^{7}}{21 x ^{6} y ^{6}}

lo g_{4} (lo g_{3} (9))

\frac{x ^{2} + 7 x - 18}{x + 9}

What is (28u^{-2}v^3)/(4u^2v^2) ?
The solution to (28u^{-2}v^3)/(4u^2v^2) is (7v)/(u^4)