What is (-5p^2q^8)/(20p^{-1)q^2} ?

The solution to (-5p^2q^8)/(20p^{-1)q^2} is -(p^3q^6)/4

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simplify (-5p^2q^8)/(20p^{-1)q^2}

simplify

\frac{- 5 p ^{2} q ^{8}}{20 p ^{- 1} q ^{2}}

- \frac{p ^{3} q ^{6}}{4}

Solution steps

\frac{- 5 p ^{2} q ^{8}}{20 p ^{- 1} q ^{2}}

Factor the number:

20 = 5 \cdot 4

= \frac{- 5 p ^{2} q ^{8}}{5 \cdot 4 p ^{- 1} q ^{2}}

Cancel the common factor:

5

= \frac{- p ^{2} q ^{8}}{4 p ^{- 1} q ^{2}}

Simplify

\frac{p ^{2}}{p ^{- 1}} : p^{3}

= \frac{- p ^{3} q ^{8}}{4 q ^{2}}

Simplify

\frac{q ^{8}}{q ^{2}} : q^{6}

= \frac{- p ^{3} q ^{6}}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{p ^{3} q ^{6}}{4}

- x \times 1

(x + a) (x^{2} - a x + a^{2})

5^{l o g_{5} (4)}

36 x^{2} + 24 x + 4

lo g_{2} ((x y)^{10})

What is (-5p^2q^8)/(20p^{-1)q^2} ?
The solution to (-5p^2q^8)/(20p^{-1)q^2} is -(p^3q^6)/4