What is factor 2x^3-9x^2+12x-4 ?

The solution to factor 2x^3-9x^2+12x-4 is (2x-1)(x-2)^2

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factor 2x^3-9x^2+12x-4

factor

2 x^{3} - 9 x^{2} + 12 x - 4

(2 x - 1) (x - 2)^{2}

Solution steps

2 x^{3} - 9 x^{2} + 12 x - 4

Use the rational root theorem

= (2 x - 1) \frac{2 x ^{3} - 9 x ^{2} + 12 x - 4}{2 x - 1}

\frac{2 x ^{3} - 9 x ^{2} + 12 x - 4}{2 x - 1} = x^{2} - 4 x + 4

= (2 x - 1) (x^{2} - 4 x + 4)

Factor

x^{2} - 4 x + 4 : (x - 2) (x - 2)

= (2 x - 1) (x - 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (2 x - 1) (x - 2)^{2}

325 + 23

\frac{1}{10} + \frac{1}{5} + \frac{1}{15}

126 \div 14

+ \frac{4 ^{5}}{4}

\frac{1}{2} (x - 3)

What is factor 2x^3-9x^2+12x-4 ?
The solution to factor 2x^3-9x^2+12x-4 is (2x-1)(x-2)^2