What is (x^2-3x-54)/(x^2-7x-18) ?

The solution to (x^2-3x-54)/(x^2-7x-18) is (x+6)/(x+2)

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simplify (x^2-3x-54)/(x^2-7x-18)

simplify

\frac{x ^{2} - 3 x - 54}{x ^{2} - 7 x - 18}

\frac{x + 6}{x + 2}

Solution steps

\frac{x ^{2} - 3 x - 54}{x ^{2} - 7 x - 18}

Factor

x^{2} - 3 x - 54 : (x + 6) (x - 9)

= \frac{( x + 6 ) ( x - 9 )}{x ^{2} - 7 x - 18}

Factor

x^{2} - 7 x - 18 : (x + 2) (x - 9)

= \frac{( x + 6 ) ( x - 9 )}{( x + 2 ) ( x - 9 )}

Cancel the common factor:

x - 9

= \frac{x + 6}{x + 2}

\frac{15}{7} \div \frac{3}{7}

+ c^{2} - 9 c d + 18 d^{2}

\frac{10}{11} - \frac{4}{7} + \frac{3}{5}

(2 n + 3)^{2}

\frac{5}{4} \times (- 4)

What is (x^2-3x-54)/(x^2-7x-18) ?
The solution to (x^2-3x-54)/(x^2-7x-18) is (x+6)/(x+2)