What is (a^{-5})^4\times a^{22} ?

The solution to (a^{-5})^4\times a^{22} is a^2

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simplify (a^{-5})^4\times a^{22}

simplify

(a^{- 5})^{4} \cdot a^{22}

a^{2}

Solution steps

(a^{- 5})^{4} a^{22}

Simplify

(a^{- 5})^{4} : \frac{1}{a ^{20}}

= \frac{1}{a ^{20}} a^{22}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot a ^{22}}{a ^{20}}

Apply rule:

1 \cdot a = a

1 \cdot a^{22} = a^{22}

= \frac{a ^{22}}{a ^{20}}

Simplify

\frac{a ^{22}}{a ^{20}} : a^{2}

= a^{2}

\frac{- 1}{10}

\frac{42}{99}

24 a^{2} + 5 ab - 14 b^{2}

- x 3 x^{5} - 3 x^{2} 3 x^{3}

10 lo g_{0.2} (x)

What is (a^{-5})^4\times a^{22} ?
The solution to (a^{-5})^4\times a^{22} is a^2