What is (7x^2-28x)/(x^2-16) ?

The solution to (7x^2-28x)/(x^2-16) is (7x)/(x+4)

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simplify (7x^2-28x)/(x^2-16)

simplify

\frac{7 x ^{2} - 28 x}{x ^{2} - 16}

\frac{7 x}{x + 4}

Solution steps

\frac{7 x ^{2} - 28 x}{x ^{2} - 16}

Factor

7 x^{2} - 28 x : 7 x (x - 4)

= \frac{7 x ( x - 4 )}{x ^{2} - 16}

Factor

x^{2} - 16 : (x + 4) (x - 4)

= \frac{7 x ( x - 4 )}{( x + 4 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{7 x}{x + 4}

(3 x + 2) (5 x + 4)

- 6 x^{2} y^{2} - 15 x^{2} y - 9 x^{2}

(t - 2) (t + 5) (t - 4)

38 \cdot 103

\frac{x ^{2} - 7 x + 10}{x ^{2} + 6 x - 16}